Thread Regex-Frage: Optionaler Anker (6 answers)
Opened by Kuerbis at 2013-04-03 09:45

Muffi
 2013-04-03 10:02
#166853 #166853
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2012-07-18
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Ich würd entweder
Code (perl): (dl )
$a =~ /^\d$/

oder ab 5.10
Code (perl): (dl )
$a ~~ [0..9]


schreiben.

[EDIT] Ich glaub das ist mein Favorit

Code (perl): (dl )
$a ~~ ['0'..'9']

Last edited: 2013-04-03 11:55:13 +0200 (CEST)
1 + 1 = 10

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