Thread $#array aber wie bei hash?
(11 answers)
Opened by mhybner at 2005-07-30 15:16
[quote=esskar,30.07.2005, 14:24]
Code: (dl
)
(scalar %$hashref) / 2 Code: (dl
)
1 c:\>perl ;) s--Pevna-;s.([a-z]).chr((ord($1)-84)%26+97).gee; s^([A-Z])^chr((ord($1)-52)%26+65)^gee;print;
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