Thread Arrays nach Hash: keine Peilung
(47 answers)
Opened by -Sven- at 2003-10-22 11:20 Quote Wieso nimmst du nicht "0..(@Server-1)"? Quote Was ist das denn?! Gruß, Erik!
s))91\&\/\^z->sub{}\(\@new\)=>69\&\/\^z->sub{}\(\@new\)=>124\&\/\^z->sub{}\(\@new\)=>); $_.=qq~66\&\/\^z->sub{}\(\@new\)=>93~;for(@_=split(/\&\/\^z->sub{}\(\@new\)=>/)){print chr;} It's not a bug, it's a feature! - [CGI-World.de] |