Thread Codeverschlüsselungstechnik (86 answers)
Opened by [E|B] at 2004-02-06 19:37

[E|B]
 2004-02-07 13:02
#79860 #79860
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2003-08-08
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Wie willst du denn Perl Code kompilieren?
Gruß, Erik!

s))91\&\/\^z->sub{}\(\@new\)=>69\&\/\^z->sub{}\(\@new\)=>124\&\/\^z->sub{}\(\@new\)=>);
$_.=qq~66\&\/\^z->sub{}\(\@new\)=>93~;for(@_=split(/\&\/\^z->sub{}\(\@new\)=>/)){print chr;}

It's not a bug, it's a feature! - [CGI-World.de]

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